-3x+4(3x-2)=-80

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Solution for -3x+4(3x-2)=-80 equation: 



-3x+4(3x-2)=-80

We move all terms to the left:

-3x+4(3x-2)-(-80)=0

We add all the numbers together, and all the variables

-3x+4(3x-2)+80=0

We multiply parentheses

-3x+12x-8+80=0

We add all the numbers together, and all the variables

9x+72=0

We move all terms containing x to the left, all other terms to the right

9x=-72

x=-72/9

x=-8

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