-3x+40=3(4x-5)-5

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Solution for -3x+40=3(4x-5)-5 equation: 



-3x+40=3(4x-5)-5

We move all terms to the left:

-3x+40-(3(4x-5)-5)=0



We calculate terms in parentheses: -(3(4x-5)-5), so:

3(4x-5)-5

We multiply parentheses

12x-15-5

We add all the numbers together, and all the variables

12x-20

Back to the equation:

-(12x-20)



We get rid of parentheses

-3x-12x+20+40=0

We add all the numbers together, and all the variables

-15x+60=0

We move all terms containing x to the left, all other terms to the right

-15x=-60

x=-60/-15

x=+4

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