-3x+4x=6(x-8)-7(-6+x)

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Solution for -3x+4x=6(x-8)-7(-6+x) equation: 



-3x+4x=6(x-8)-7(-6+x)

We move all terms to the left:

-3x+4x-(6(x-8)-7(-6+x))=0

We add all the numbers together, and all the variables

-3x+4x-(6(x-8)-7(x-6))=0

We add all the numbers together, and all the variables

x-(6(x-8)-7(x-6))=0



We calculate terms in parentheses: -(6(x-8)-7(x-6)), so:

6(x-8)-7(x-6)

We multiply parentheses

6x-7x-48+42

We add all the numbers together, and all the variables

-1x-6

Back to the equation:

-(-1x-6)



We get rid of parentheses

x+1x+6=0

We add all the numbers together, and all the variables

2x+6=0

We move all terms containing x to the left, all other terms to the right

2x=-6

x=-6/2

x=-3

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