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-3x+6x-16=3(x-1)-32
We move all terms to the left:
-3x+6x-16-(3(x-1)-32)=0
We add all the numbers together, and all the variables
3x-(3(x-1)-32)-16=0
We calculate terms in parentheses: -(3(x-1)-32), so:We get rid of parentheses
3(x-1)-32
We multiply parentheses
3x-3-32
We add all the numbers together, and all the variables
3x-35
Back to the equation:
-(3x-35)
3x-3x+35-16=0
We add all the numbers together, and all the variables
19!=0
There is no solution for this equation
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