-3x+6x-8=3(x-4)-4

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Solution for -3x+6x-8=3(x-4)-4 equation: 



-3x+6x-8=3(x-4)-4

We move all terms to the left:

-3x+6x-8-(3(x-4)-4)=0

We add all the numbers together, and all the variables

3x-(3(x-4)-4)-8=0



We calculate terms in parentheses: -(3(x-4)-4), so:

3(x-4)-4

We multiply parentheses

3x-12-4

We add all the numbers together, and all the variables

3x-16

Back to the equation:

-(3x-16)



We get rid of parentheses

3x-3x+16-8=0

We add all the numbers together, and all the variables

8!=0

There is no solution for this equation

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