-3x+6x-8=3(x-6)2

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Solution for -3x+6x-8=3(x-6)2 equation: 



-3x+6x-8=3(x-6)2

We move all terms to the left:

-3x+6x-8-(3(x-6)2)=0

We add all the numbers together, and all the variables

3x-(3(x-6)2)-8=0



We calculate terms in parentheses: -(3(x-6)2), so:

3(x-6)2

We multiply parentheses

6x-36

Back to the equation:

-(6x-36)



We get rid of parentheses

3x-6x+36-8=0

We add all the numbers together, and all the variables

-3x+28=0

We move all terms containing x to the left, all other terms to the right

-3x=-28

x=-28/-3

x=9+1/3

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