-3x+7((3x+13)/7)=13

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Solution for -3x+7((3x+13)/7)=13 equation: 



-3x+7((3x+13)/7)=13

We move all terms to the left:

-3x+7((3x+13)/7)-(13)=0

We multiply all the terms by the denominator


-3x*7)+7((3x+13)-13*7)=0

We add all the numbers together, and all the variables

-3x*7)+7((3x+13)=0

Wy multiply elements

-21x^2=0

a = -21; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-21)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-42}=0$

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