-3x+8(3x-4)+19=13-5(2x-6)-4+x

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Solution for -3x+8(3x-4)+19=13-5(2x-6)-4+x equation: 



-3x+8(3x-4)+19=13-5(2x-6)-4+x

We move all terms to the left:

-3x+8(3x-4)+19-(13-5(2x-6)-4+x)=0

We multiply parentheses

-3x+24x-(13-5(2x-6)-4+x)-32+19=0



We calculate terms in parentheses: -(13-5(2x-6)-4+x), so:

13-5(2x-6)-4+x

determiningTheFunctionDomain
-5(2x-6)+x+13-4

We add all the numbers together, and all the variables

x-5(2x-6)+9

We multiply parentheses

x-10x+30+9

We add all the numbers together, and all the variables

-9x+39

Back to the equation:

-(-9x+39)



We add all the numbers together, and all the variables

21x-(-9x+39)-13=0

We get rid of parentheses

21x+9x-39-13=0

We add all the numbers together, and all the variables

30x-52=0

We move all terms containing x to the left, all other terms to the right

30x=52

x=52/30

x=1+11/15

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