-3x+8(3x-4)+19=13-5(2x-6)-5+2x

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Solution for -3x+8(3x-4)+19=13-5(2x-6)-5+2x equation: 



-3x+8(3x-4)+19=13-5(2x-6)-5+2x

We move all terms to the left:

-3x+8(3x-4)+19-(13-5(2x-6)-5+2x)=0

We multiply parentheses

-3x+24x-(13-5(2x-6)-5+2x)-32+19=0



We calculate terms in parentheses: -(13-5(2x-6)-5+2x), so:

13-5(2x-6)-5+2x

determiningTheFunctionDomain
-5(2x-6)+2x+13-5

We add all the numbers together, and all the variables

2x-5(2x-6)+8

We multiply parentheses

2x-10x+30+8

We add all the numbers together, and all the variables

-8x+38

Back to the equation:

-(-8x+38)



We add all the numbers together, and all the variables

21x-(-8x+38)-13=0

We get rid of parentheses

21x+8x-38-13=0

We add all the numbers together, and all the variables

29x-51=0

We move all terms containing x to the left, all other terms to the right

29x=51

x=51/29

x=1+22/29

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