-3x+8(x-4)=3x-40

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Solution for -3x+8(x-4)=3x-40 equation: 



-3x+8(x-4)=3x-40

We move all terms to the left:

-3x+8(x-4)-(3x-40)=0

We multiply parentheses

-3x+8x-(3x-40)-32=0

We get rid of parentheses

-3x+8x-3x+40-32=0

We add all the numbers together, and all the variables

2x+8=0

We move all terms containing x to the left, all other terms to the right

2x=-8

x=-8/2

x=-4

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