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-3x+9=2x(x+7)
We move all terms to the left:
-3x+9-(2x(x+7))=0
We calculate terms in parentheses: -(2x(x+7)), so:We get rid of parentheses
2x(x+7)
We multiply parentheses
2x^2+14x
Back to the equation:
-(2x^2+14x)
-2x^2-3x-14x+9=0
We add all the numbers together, and all the variables
-2x^2-17x+9=0
a = -2; b = -17; c = +9;
Δ = b2-4ac
Δ = -172-4·(-2)·9
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{361}=19$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-19}{2*-2}=\frac{-2}{-4} =1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+19}{2*-2}=\frac{36}{-4} =-9 $
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