-3x+x=(-1x)x=6

Solution for -3x+x=(-1x)x=6 equation:

-3x+x=(-1x)x=6

We move all terms to the left:

-3x+x-((-1x)x)=0

We add all the numbers together, and all the variables

-2x-((-1x)x)=0


We calculate terms in parentheses: -((-1x)x), so:

(-1x)x

We multiply parentheses

-1x^2

Back to the equation:

-(-1x^2)


We get rid of parentheses

1x^2-2x=0

We add all the numbers together, and all the variables

x^2-2x=0

a = 1; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·1·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*1}=\frac{0}{2}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*1}=\frac{4}{2}
=2
$