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-3x-10+5x=2(x-5)
We move all terms to the left:
-3x-10+5x-(2(x-5))=0
We add all the numbers together, and all the variables
2x-(2(x-5))-10=0
We calculate terms in parentheses: -(2(x-5)), so:We get rid of parentheses
2(x-5)
We multiply parentheses
2x-10
Back to the equation:
-(2x-10)
2x-2x+10-10=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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