-3x-2-5(7-8x)=4x+3x-(2x+3)+27x

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Solution for -3x-2-5(7-8x)=4x+3x-(2x+3)+27x equation: 



-3x-2-5(7-8x)=4x+3x-(2x+3)+27x

We move all terms to the left:

-3x-2-5(7-8x)-(4x+3x-(2x+3)+27x)=0

We add all the numbers together, and all the variables

-3x-5(-8x+7)-(4x+3x-(2x+3)+27x)-2=0

We multiply parentheses

-3x+40x-(4x+3x-(2x+3)+27x)-35-2=0



We calculate terms in parentheses: -(4x+3x-(2x+3)+27x), so:

4x+3x-(2x+3)+27x

We add all the numbers together, and all the variables

34x-(2x+3)

We get rid of parentheses

34x-2x-3

We add all the numbers together, and all the variables

32x-3

Back to the equation:

-(32x-3)



We add all the numbers together, and all the variables

37x-(32x-3)-37=0

We get rid of parentheses

37x-32x+3-37=0

We add all the numbers together, and all the variables

5x-34=0

We move all terms containing x to the left, all other terms to the right

5x=34

x=34/5

x=6+4/5

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