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-3x-3+5x-1=2(x-2)
We move all terms to the left:
-3x-3+5x-1-(2(x-2))=0
We add all the numbers together, and all the variables
2x-(2(x-2))-4=0
We calculate terms in parentheses: -(2(x-2)), so:We get rid of parentheses
2(x-2)
We multiply parentheses
2x-4
Back to the equation:
-(2x-4)
2x-2x+4-4=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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