-3x-3=-3(1+8x)/2

Solution for -3x-3=-3(1+8x)/2 equation:

-3x-3=-3(1+8x)/2

We move all terms to the left:

-3x-3-(-3(1+8x)/2)=0

We add all the numbers together, and all the variables

-3x-(-3(8x+1)/2)-3=0

We multiply all the terms by the denominator


-3x*2)-(-3(8x+1)-3*2)=0

We add all the numbers together, and all the variables

-3x*2)-(-3(8x+1)=0

We multiply parentheses

-3x*2)-(-24x-3=0

Wy multiply elements

-6x^2-24x-3=0

a = -6; b = -24; c = -3;
Δ = b2-4ac
Δ = -242-4·(-6)·(-3)
Δ = 504
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{504}=\sqrt{36*14}=\sqrt{36}*\sqrt{14}=6\sqrt{14}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-6\sqrt{14}}{2*-6}=\frac{24-6\sqrt{14}}{-12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+6\sqrt{14}}{2*-6}=\frac{24+6\sqrt{14}}{-12}
$