-3x-3x=-4x(2x+7)

Solution for -3x-3x=-4x(2x+7) equation:

-3x-3x=-4x(2x+7)

We move all terms to the left:

-3x-3x-(-4x(2x+7))=0

We add all the numbers together, and all the variables

-6x-(-4x(2x+7))=0


We calculate terms in parentheses: -(-4x(2x+7)), so:

-4x(2x+7)

We multiply parentheses

-8x^2-28x

Back to the equation:

-(-8x^2-28x)


We get rid of parentheses

8x^2+28x-6x=0

We add all the numbers together, and all the variables

8x^2+22x=0

a = 8; b = 22; c = 0;
Δ = b2-4ac
Δ = 222-4·8·0
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{484}=22$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-22}{2*8}=\frac{-44}{16}
=-2+3/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+22}{2*8}=\frac{0}{16}
=0
$