-3x-4(2-3x)=3(x-5)-23

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Solution for -3x-4(2-3x)=3(x-5)-23 equation: 



-3x-4(2-3x)=3(x-5)-23

We move all terms to the left:

-3x-4(2-3x)-(3(x-5)-23)=0

We add all the numbers together, and all the variables

-3x-4(-3x+2)-(3(x-5)-23)=0

We multiply parentheses

-3x+12x-(3(x-5)-23)-8=0



We calculate terms in parentheses: -(3(x-5)-23), so:

3(x-5)-23

We multiply parentheses

3x-15-23

We add all the numbers together, and all the variables

3x-38

Back to the equation:

-(3x-38)



We add all the numbers together, and all the variables

9x-(3x-38)-8=0

We get rid of parentheses

9x-3x+38-8=0

We add all the numbers together, and all the variables

6x+30=0

We move all terms containing x to the left, all other terms to the right

6x=-30

x=-30/6

x=-5

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