-3x-4(3x+-3)=2

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Solution for -3x-4(3x+-3)=2 equation: 



-3x-4(3x+-3)=2

We move all terms to the left:

-3x-4(3x+-3)-(2)=0

We add all the numbers together, and all the variables

-3x-4(3x-3)-2=0

We multiply parentheses

-3x-12x+12-2=0

We add all the numbers together, and all the variables

-15x+10=0

We move all terms containing x to the left, all other terms to the right

-15x=-10

x=-10/-15

x=2/3

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