-3x-4(4-3x)=3(x-3)-31

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Solution for -3x-4(4-3x)=3(x-3)-31 equation: 



-3x-4(4-3x)=3(x-3)-31

We move all terms to the left:

-3x-4(4-3x)-(3(x-3)-31)=0

We add all the numbers together, and all the variables

-3x-4(-3x+4)-(3(x-3)-31)=0

We multiply parentheses

-3x+12x-(3(x-3)-31)-16=0



We calculate terms in parentheses: -(3(x-3)-31), so:

3(x-3)-31

We multiply parentheses

3x-9-31

We add all the numbers together, and all the variables

3x-40

Back to the equation:

-(3x-40)



We add all the numbers together, and all the variables

9x-(3x-40)-16=0

We get rid of parentheses

9x-3x+40-16=0

We add all the numbers together, and all the variables

6x+24=0

We move all terms containing x to the left, all other terms to the right

6x=-24

x=-24/6

x=-4

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