-3x-4(4x-8)=3-(8x+1)

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Solution for -3x-4(4x-8)=3-(8x+1) equation: 



-3x-4(4x-8)=3-(8x+1)

We move all terms to the left:

-3x-4(4x-8)-(3-(8x+1))=0

We multiply parentheses

-3x-16x-(3-(8x+1))+32=0



We calculate terms in parentheses: -(3-(8x+1)), so:

3-(8x+1)

determiningTheFunctionDomain
-(8x+1)+3

We get rid of parentheses

-8x-1+3

We add all the numbers together, and all the variables

-8x+2

Back to the equation:

-(-8x+2)



We add all the numbers together, and all the variables

-19x-(-8x+2)+32=0

We get rid of parentheses

-19x+8x-2+32=0

We add all the numbers together, and all the variables

-11x+30=0

We move all terms containing x to the left, all other terms to the right

-11x=-30

x=-30/-11

x=2+8/11

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