-3x-4(8x+1)=3(7x-1)

Solution for -3x-4(8x+1)=3(7x-1) equation:

-3x-4(8x+1)=3(7x-1)

We move all terms to the left:

-3x-4(8x+1)-(3(7x-1))=0

We multiply parentheses

-3x-32x-(3(7x-1))-4=0


We calculate terms in parentheses: -(3(7x-1)), so:

3(7x-1)

We multiply parentheses

21x-3

Back to the equation:

-(21x-3)


We add all the numbers together, and all the variables

-35x-(21x-3)-4=0

We get rid of parentheses

-35x-21x+3-4=0

We add all the numbers together, and all the variables

-56x-1=0

We move all terms containing x to the left, all other terms to the right

-56x=1

x=1/-56

x=-1/56