-3x-4(x-8)-12=48

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Solution for -3x-4(x-8)-12=48 equation: 



-3x-4(x-8)-12=48

We move all terms to the left:

-3x-4(x-8)-12-(48)=0

We add all the numbers together, and all the variables

-3x-4(x-8)-60=0

We multiply parentheses

-3x-4x+32-60=0

We add all the numbers together, and all the variables

-7x-28=0

We move all terms containing x to the left, all other terms to the right

-7x=28

x=28/-7

x=-4

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