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-3x^2+2+6x+144=0
We add all the numbers together, and all the variables
-3x^2+6x+146=0
a = -3; b = 6; c = +146;
Δ = b2-4ac
Δ = 62-4·(-3)·146
Δ = 1788
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1788}=\sqrt{4*447}=\sqrt{4}*\sqrt{447}=2\sqrt{447}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{447}}{2*-3}=\frac{-6-2\sqrt{447}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{447}}{2*-3}=\frac{-6+2\sqrt{447}}{-6} $
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