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-3x^2+28x-9=0
a = -3; b = 28; c = -9;
Δ = b2-4ac
Δ = 282-4·(-3)·(-9)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{676}=26$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-26}{2*-3}=\frac{-54}{-6} =+9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+26}{2*-3}=\frac{-2}{-6} =1/3 $
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