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-3x^2+30x-48=0
a = -3; b = 30; c = -48;
Δ = b2-4ac
Δ = 302-4·(-3)·(-48)
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-18}{2*-3}=\frac{-48}{-6} =+8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+18}{2*-3}=\frac{-12}{-6} =+2 $
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