-3x2+36x-108=0

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Solution for -3x2+36x-108=0 equation: 



-3x^2+36x-108=0

a = -3; b = 36; c = -108;
Δ = b2-4ac
Δ = 362-4·(-3)·(-108)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-36}{-6}=+6$

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