-3x2+5=14x

Solution for -3x2+5=14x equation:

-3x^2+5=14x

We move all terms to the left:

-3x^2+5-(14x)=0

a = -3; b = -14; c = +5;
Δ = b2-4ac
Δ = -142-4·(-3)·5
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-16}{2*-3}=\frac{-2}{-6}
=1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+16}{2*-3}=\frac{30}{-6}
=-5
$