-3x2+9x-6=0

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Solution for -3x2+9x-6=0 equation: 



-3x^2+9x-6=0

a = -3; b = 9; c = -6;
Δ = b2-4ac
Δ = 92-4·(-3)·(-6)
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-3}{2*-3}=\frac{-12}{-6}
=+2
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+3}{2*-3}=\frac{-6}{-6}
=1
$

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