-3x2-4x+7=0

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Solution for -3x2-4x+7=0 equation:



-3x^2-4x+7=0
a = -3; b = -4; c = +7;
Δ = b2-4ac
Δ = -42-4·(-3)·7
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-10}{2*-3}=\frac{-6}{-6} =1 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+10}{2*-3}=\frac{14}{-6} =-2+1/3 $

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