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-3x^2-7x+5=4x
We move all terms to the left:
-3x^2-7x+5-(4x)=0
We add all the numbers together, and all the variables
-3x^2-11x+5=0
a = -3; b = -11; c = +5;
Δ = b2-4ac
Δ = -112-4·(-3)·5
Δ = 181
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-\sqrt{181}}{2*-3}=\frac{11-\sqrt{181}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+\sqrt{181}}{2*-3}=\frac{11+\sqrt{181}}{-6} $
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