-3y(5y-3)-y=-2(y-5)

Solution for -3y(5y-3)-y=-2(y-5) equation:

-3y(5y-3)-y=-2(y-5)

We move all terms to the left:

-3y(5y-3)-y-(-2(y-5))=0

We add all the numbers together, and all the variables

-1y-3y(5y-3)-(-2(y-5))=0

We multiply parentheses

-15y^2-1y+9y-(-2(y-5))=0


We calculate terms in parentheses: -(-2(y-5)), so:

-2(y-5)

We multiply parentheses

-2y+10

Back to the equation:

-(-2y+10)


We add all the numbers together, and all the variables

-15y^2+8y-(-2y+10)=0

We get rid of parentheses

-15y^2+8y+2y-10=0

We add all the numbers together, and all the variables

-15y^2+10y-10=0

a = -15; b = 10; c = -10;
Δ = b2-4ac
Δ = 102-4·(-15)·(-10)
Δ = -500
Delta is less than zero, so there is no solution for the equation