-3y(6y-6)+7y=3(y+8)

Solution for -3y(6y-6)+7y=3(y+8) equation:

-3y(6y-6)+7y=3(y+8)

We move all terms to the left:

-3y(6y-6)+7y-(3(y+8))=0

We add all the numbers together, and all the variables

7y-3y(6y-6)-(3(y+8))=0

We multiply parentheses

-18y^2+7y+18y-(3(y+8))=0


We calculate terms in parentheses: -(3(y+8)), so:

3(y+8)

We multiply parentheses

3y+24

Back to the equation:

-(3y+24)


We add all the numbers together, and all the variables

-18y^2+25y-(3y+24)=0

We get rid of parentheses

-18y^2+25y-3y-24=0

We add all the numbers together, and all the variables

-18y^2+22y-24=0

a = -18; b = 22; c = -24;
Δ = b2-4ac
Δ = 222-4·(-18)·(-24)
Δ = -1244
Delta is less than zero, so there is no solution for the equation