-3y+(1y+9)=9+4(-8-y)

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Solution for -3y+(1y+9)=9+4(-8-y) equation: 



-3y+(1y+9)=9+4(-8-y)

We move all terms to the left:

-3y+(1y+9)-(9+4(-8-y))=0

We add all the numbers together, and all the variables

-3y+(y+9)-(9+4(-1y-8))=0

We get rid of parentheses

-3y+y-(9+4(-1y-8))+9=0



We calculate terms in parentheses: -(9+4(-1y-8)), so:

9+4(-1y-8)

determiningTheFunctionDomain
4(-1y-8)+9

We multiply parentheses

-4y-32+9

We add all the numbers together, and all the variables

-4y-23

Back to the equation:

-(-4y-23)



We add all the numbers together, and all the variables

-2y-(-4y-23)+9=0

We get rid of parentheses

-2y+4y+23+9=0

We add all the numbers together, and all the variables

2y+32=0

We move all terms containing y to the left, all other terms to the right

2y=-32

y=-32/2

y=-16

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