-3y+(5y-1)=2(y-4)+3

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Solution for -3y+(5y-1)=2(y-4)+3 equation: 



-3y+(5y-1)=2(y-4)+3

We move all terms to the left:

-3y+(5y-1)-(2(y-4)+3)=0

We get rid of parentheses

-3y+5y-(2(y-4)+3)-1=0



We calculate terms in parentheses: -(2(y-4)+3), so:

2(y-4)+3

We multiply parentheses

2y-8+3

We add all the numbers together, and all the variables

2y-5

Back to the equation:

-(2y-5)



We add all the numbers together, and all the variables

2y-(2y-5)-1=0

We get rid of parentheses

2y-2y+5-1=0

We add all the numbers together, and all the variables

4!=0

There is no solution for this equation

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