-3y+10=2(y-5)

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Solution for -3y+10=2(y-5) equation: 



-3y+10=2(y-5)

We move all terms to the left:

-3y+10-(2(y-5))=0



We calculate terms in parentheses: -(2(y-5)), so:

2(y-5)

We multiply parentheses

2y-10

Back to the equation:

-(2y-10)



We get rid of parentheses

-3y-2y+10+10=0

We add all the numbers together, and all the variables

-5y+20=0

We move all terms containing y to the left, all other terms to the right

-5y=-20

y=-20/-5

y=+4

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