-3y+12=-3(2y+12)

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Solution for -3y+12=-3(2y+12) equation: 



-3y+12=-3(2y+12)

We move all terms to the left:

-3y+12-(-3(2y+12))=0



We calculate terms in parentheses: -(-3(2y+12)), so:

-3(2y+12)

We multiply parentheses

-6y-36

Back to the equation:

-(-6y-36)



We get rid of parentheses

-3y+6y+36+12=0

We add all the numbers together, and all the variables

3y+48=0

We move all terms containing y to the left, all other terms to the right

3y=-48

y=-48/3

y=-16

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