-3y+6=(4y-1)=0

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Solution for -3y+6=(4y-1)=0 equation: 



-3y+6=(4y-1)=0

We move all terms to the left:

-3y+6-((4y-1))=0



We calculate terms in parentheses: -((4y-1)), so:

(4y-1)

We get rid of parentheses

4y-1

Back to the equation:

-(4y-1)



We get rid of parentheses

-3y-4y+1+6=0

We add all the numbers together, and all the variables

-7y+7=0

We move all terms containing y to the left, all other terms to the right

-7y=-7

y=-7/-7

y=1

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