-3y+8(-1y-2)=7-6(2-y)

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Solution for -3y+8(-1y-2)=7-6(2-y) equation:



-3y+8(-1y-2)=7-6(2-y)
We move all terms to the left:
-3y+8(-1y-2)-(7-6(2-y))=0
We add all the numbers together, and all the variables
-3y+8(-1y-2)-(7-6(-1y+2))=0
We multiply parentheses
-3y-8y-(7-6(-1y+2))-16=0
We calculate terms in parentheses: -(7-6(-1y+2)), so:
7-6(-1y+2)
determiningTheFunctionDomain -6(-1y+2)+7
We multiply parentheses
6y-12+7
We add all the numbers together, and all the variables
6y-5
Back to the equation:
-(6y-5)
We add all the numbers together, and all the variables
-11y-(6y-5)-16=0
We get rid of parentheses
-11y-6y+5-16=0
We add all the numbers together, and all the variables
-17y-11=0
We move all terms containing y to the left, all other terms to the right
-17y=11
y=11/-17
y=-11/17

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