-3y-(2y-8)=-y+3(y-1)

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Solution for -3y-(2y-8)=-y+3(y-1) equation: 



-3y-(2y-8)=-y+3(y-1)

We move all terms to the left:

-3y-(2y-8)-(-y+3(y-1))=0

We get rid of parentheses

-3y-2y-(-y+3(y-1))+8=0



We calculate terms in parentheses: -(-y+3(y-1)), so:

-y+3(y-1)

We add all the numbers together, and all the variables

-1y+3(y-1)

We multiply parentheses

-1y+3y-3

We add all the numbers together, and all the variables

2y-3

Back to the equation:

-(2y-3)



We add all the numbers together, and all the variables

-5y-(2y-3)+8=0

We get rid of parentheses

-5y-2y+3+8=0

We add all the numbers together, and all the variables

-7y+11=0

We move all terms containing y to the left, all other terms to the right

-7y=-11

y=-11/-7

y=1+4/7

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