-3y-12=2(3y+3)

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Solution for -3y-12=2(3y+3) equation:



-3y-12=2(3y+3)
We move all terms to the left:
-3y-12-(2(3y+3))=0
We calculate terms in parentheses: -(2(3y+3)), so:
2(3y+3)
We multiply parentheses
6y+6
Back to the equation:
-(6y+6)
We get rid of parentheses
-3y-6y-6-12=0
We add all the numbers together, and all the variables
-9y-18=0
We move all terms containing y to the left, all other terms to the right
-9y=18
y=18/-9
y=-2

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