-3y-12=2(3y+3)

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Solution for -3y-12=2(3y+3) equation: 



-3y-12=2(3y+3)

We move all terms to the left:

-3y-12-(2(3y+3))=0



We calculate terms in parentheses: -(2(3y+3)), so:

2(3y+3)

We multiply parentheses

6y+6

Back to the equation:

-(6y+6)



We get rid of parentheses

-3y-6y-6-12=0

We add all the numbers together, and all the variables

-9y-18=0

We move all terms containing y to the left, all other terms to the right

-9y=18

y=18/-9

y=-2

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