-3y-5y*(y+4)=4

Solution for -3y-5y*(y+4)=4 equation:

-3y-5y(y+4)=4

We move all terms to the left:

-3y-5y(y+4)-(4)=0

We multiply parentheses

-5y^2-3y-20y-4=0

We add all the numbers together, and all the variables

-5y^2-23y-4=0

a = -5; b = -23; c = -4;
Δ = b2-4ac
Δ = -232-4·(-5)·(-4)
Δ = 449
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-23)-\sqrt{449}}{2*-5}=\frac{23-\sqrt{449}}{-10}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-23)+\sqrt{449}}{2*-5}=\frac{23+\sqrt{449}}{-10}
$