-3z+10-2z=-2(z-5)+5

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Solution for -3z+10-2z=-2(z-5)+5 equation: 



-3z+10-2z=-2(z-5)+5

We move all terms to the left:

-3z+10-2z-(-2(z-5)+5)=0

We add all the numbers together, and all the variables

-5z-(-2(z-5)+5)+10=0



We calculate terms in parentheses: -(-2(z-5)+5), so:

-2(z-5)+5

We multiply parentheses

-2z+10+5

We add all the numbers together, and all the variables

-2z+15

Back to the equation:

-(-2z+15)



We get rid of parentheses

-5z+2z-15+10=0

We add all the numbers together, and all the variables

-3z-5=0

We move all terms containing z to the left, all other terms to the right

-3z=5

z=5/-3

z=-1+2/3

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