-4((8y+6)-3(y-2))=6(3-y)-3

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Solution for -4((8y+6)-3(y-2))=6(3-y)-3 equation: 



-4((8y+6)-3(y-2))=6(3-y)-3

We move all terms to the left:

-4((8y+6)-3(y-2))-(6(3-y)-3)=0

We add all the numbers together, and all the variables

-4((8y+6)-3(y-2))-(6(-1y+3)-3)=0



We calculate terms in parentheses: -(6(-1y+3)-3), so:

6(-1y+3)-3

We multiply parentheses

-6y+18-3

We add all the numbers together, and all the variables

-6y+15

Back to the equation:

-(-6y+15)



We get rid of parentheses

-4((8y+6)-3(y-2))+6y-15=0

We add all the numbers together, and all the variables

6y-4((8y+6)-3(y-2))-15=0

We move all terms containing y to the left, all other terms to the right

6y-4((8y+6)-3(y-2))=15

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