-4(-10z+1)+12=20(2z+5)-92

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Solution for -4(-10z+1)+12=20(2z+5)-92 equation:


Simplifying
-4(-10z + 1) + 12 = 20(2z + 5) + -92

Reorder the terms:
-4(1 + -10z) + 12 = 20(2z + 5) + -92
(1 * -4 + -10z * -4) + 12 = 20(2z + 5) + -92
(-4 + 40z) + 12 = 20(2z + 5) + -92

Reorder the terms:
-4 + 12 + 40z = 20(2z + 5) + -92

Combine like terms: -4 + 12 = 8
8 + 40z = 20(2z + 5) + -92

Reorder the terms:
8 + 40z = 20(5 + 2z) + -92
8 + 40z = (5 * 20 + 2z * 20) + -92
8 + 40z = (100 + 40z) + -92

Reorder the terms:
8 + 40z = 100 + -92 + 40z

Combine like terms: 100 + -92 = 8
8 + 40z = 8 + 40z

Add '-8' to each side of the equation.
8 + -8 + 40z = 8 + -8 + 40z

Combine like terms: 8 + -8 = 0
0 + 40z = 8 + -8 + 40z
40z = 8 + -8 + 40z

Combine like terms: 8 + -8 = 0
40z = 0 + 40z
40z = 40z

Add '-40z' to each side of the equation.
40z + -40z = 40z + -40z

Combine like terms: 40z + -40z = 0
0 = 40z + -40z

Combine like terms: 40z + -40z = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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