-4(-12q+8)=-6(q-18)+12q

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Solution for -4(-12q+8)=-6(q-18)+12q equation: 



-4(-12q+8)=-6(q-18)+12q

We move all terms to the left:

-4(-12q+8)-(-6(q-18)+12q)=0

We multiply parentheses

48q-(-6(q-18)+12q)-32=0



We calculate terms in parentheses: -(-6(q-18)+12q), so:

-6(q-18)+12q

We add all the numbers together, and all the variables

12q-6(q-18)

We multiply parentheses

12q-6q+108

We add all the numbers together, and all the variables

6q+108

Back to the equation:

-(6q+108)



We get rid of parentheses

48q-6q-108-32=0

We add all the numbers together, and all the variables

42q-140=0

We move all terms containing q to the left, all other terms to the right

42q=140

q=140/42

q=3+1/3

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