-4(-2q+8)=6(q-18)+12q

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Solution for -4(-2q+8)=6(q-18)+12q equation: 



-4(-2q+8)=6(q-18)+12q

We move all terms to the left:

-4(-2q+8)-(6(q-18)+12q)=0

We multiply parentheses

8q-(6(q-18)+12q)-32=0



We calculate terms in parentheses: -(6(q-18)+12q), so:

6(q-18)+12q

We add all the numbers together, and all the variables

12q+6(q-18)

We multiply parentheses

12q+6q-108

We add all the numbers together, and all the variables

18q-108

Back to the equation:

-(18q-108)



We get rid of parentheses

8q-18q+108-32=0

We add all the numbers together, and all the variables

-10q+76=0

We move all terms containing q to the left, all other terms to the right

-10q=-76

q=-76/-10

q=7+3/5

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