-4(-2x+1)-x=3(x-4)-2

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Solution for -4(-2x+1)-x=3(x-4)-2 equation: 



-4(-2x+1)-x=3(x-4)-2

We move all terms to the left:

-4(-2x+1)-x-(3(x-4)-2)=0

We add all the numbers together, and all the variables

-1x-4(-2x+1)-(3(x-4)-2)=0

We multiply parentheses

-1x+8x-(3(x-4)-2)-4=0



We calculate terms in parentheses: -(3(x-4)-2), so:

3(x-4)-2

We multiply parentheses

3x-12-2

We add all the numbers together, and all the variables

3x-14

Back to the equation:

-(3x-14)



We add all the numbers together, and all the variables

7x-(3x-14)-4=0

We get rid of parentheses

7x-3x+14-4=0

We add all the numbers together, and all the variables

4x+10=0

We move all terms containing x to the left, all other terms to the right

4x=-10

x=-10/4

x=-2+1/2

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