-4(-3y+2)-3y=3(y-4)-4

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Solution for -4(-3y+2)-3y=3(y-4)-4 equation: 



-4(-3y+2)-3y=3(y-4)-4

We move all terms to the left:

-4(-3y+2)-3y-(3(y-4)-4)=0

We add all the numbers together, and all the variables

-3y-4(-3y+2)-(3(y-4)-4)=0

We multiply parentheses

-3y+12y-(3(y-4)-4)-8=0



We calculate terms in parentheses: -(3(y-4)-4), so:

3(y-4)-4

We multiply parentheses

3y-12-4

We add all the numbers together, and all the variables

3y-16

Back to the equation:

-(3y-16)



We add all the numbers together, and all the variables

9y-(3y-16)-8=0

We get rid of parentheses

9y-3y+16-8=0

We add all the numbers together, and all the variables

6y+8=0

We move all terms containing y to the left, all other terms to the right

6y=-8

y=-8/6

y=-1+1/3

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