-4(-4v+2)-2v=2(v-2)-1

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Solution for -4(-4v+2)-2v=2(v-2)-1 equation: 



-4(-4v+2)-2v=2(v-2)-1

We move all terms to the left:

-4(-4v+2)-2v-(2(v-2)-1)=0

We add all the numbers together, and all the variables

-2v-4(-4v+2)-(2(v-2)-1)=0

We multiply parentheses

-2v+16v-(2(v-2)-1)-8=0



We calculate terms in parentheses: -(2(v-2)-1), so:

2(v-2)-1

We multiply parentheses

2v-4-1

We add all the numbers together, and all the variables

2v-5

Back to the equation:

-(2v-5)



We add all the numbers together, and all the variables

14v-(2v-5)-8=0

We get rid of parentheses

14v-2v+5-8=0

We add all the numbers together, and all the variables

12v-3=0

We move all terms containing v to the left, all other terms to the right

12v=3

v=3/12

v=1/4

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